log[4]x-log[4](2x-4)=3

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Solution for log[4]x-log[4](2x-4)=3 equation:


Simplifying
log[4] * x + -1log[4](2x + -4) = 3

Reorder the terms for easier multiplication:
4glo * x + -1log[4](2x + -4) = 3

Multiply glo * x
4glox + -1log[4](2x + -4) = 3

Reorder the terms:
4glox + -1glo * 4(-4 + 2x) = 3

Reorder the terms for easier multiplication:
4glox + -1 * 4glo(-4 + 2x) = 3

Multiply -1 * 4
4glox + -4glo(-4 + 2x) = 3
4glox + (-4 * -4glo + 2x * -4glo) = 3
4glox + (16glo + -8glox) = 3

Reorder the terms:
16glo + 4glox + -8glox = 3

Combine like terms: 4glox + -8glox = -4glox
16glo + -4glox = 3

Solving
16glo + -4glox = 3

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-3 + 16glo + -4glox = 3 + -3

Combine like terms: 3 + -3 = 0
-3 + 16glo + -4glox = 0

The solution to this equation could not be determined.

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